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OK, here is my story on the back brakes on my trike. When
I took my trike for the first test run everything worked fine except...
well you guessed it.. the rear brakes. I had installed a 1960 Ford master
cylinder, I thought it would be perfect, one line output and big enough
to stop a Truck. Boy was I wrong, I had little to NO brakes and the pedal
was stiff as a board. I thought the original Master should do it, so I
bought a new ($60) VW Beetle Master Cylinder. The brakes where a little
better, but still far from good. The brake wheel cylinder where new, so
where the shoes, the adjusters and the brake lines. Basically everything
from the master cylinder to the wheels have been replaced. So what's the
problem?? Here I quote Trader and Lloyd who can explain it better.
| The ratio of the diameter of the plunger in the master cylinder to
the
diameter of the piston in the slave or wheel cylinder has EVERYTHING to do with braking. If the diameter of the plunger in the master cylinder is greater than the diameter of the piston in the wheel cylinder you won't have any brakes because you have no advantage. Also the distance between the pivot point of the brake pedal to the footpad is very important. The longer the pedal the more mechanical advantage you have. The bore of the master cylinder should always be smaller than the bore of the slave cylinder. You pick up the extra fluid to operate more than one wheel cylinder by the simple fact that the stroke of the master cylinder is much more than that of the slave cylinder. The rear brakes of a VW are weak at best. If everything is not just right they don't exist. TRADER |
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advantage you can possibly have. Let me try to explain this in a different way then Trader, even though the out come will be exactly the same. Assume: 2 wheel cyl.'s w/ a surface area of 1 inch each = 2 inches total reacting surface area 1 mstr. cyl w/ a surface area of 1/2 inches = 1/2 inches total acting surface area If each wheel cyl. must move 1/2 inch to lock up the brakes you have a volume change of 1x1/2= 1/2 in each cyl, which = total volume change in bot wheel cyl.'s of 1 cubic inch ( assuming the are single acting wheel cyl.'s. In order for the master cyl. to "move" 1 cubic inch of fluid it must travel (move) 2 inches (1=1/2xV; 1x2=1/2x2xV; 2=1V; 2=V; V=2). I hope this helps. Obviously it is simplified and assumes alot,
but that's the easiest way of
Lloyd "Meat" |
OK. now I know... but what can I
do about it? First thing I thought was, "well if the Master Cylinder is
missing to operate four wheel cylinder I'll give him four to operate. My
idea is ( haven't tried it yet ) to connect two extra 'blind' wheel cylinder
to the system. The only function those two would have is to give the master
cylinder the volume it needs. I would restrict both sides of the wheel
cylinder to prevent the pistons from popping out and mount them where they
are not in the way.
My second idea is to connect the front brakes ( 500 Honda
Dirt bike fork and brake ) to the Master Cylinder. I have done this and
it works well. I have more brake power because of the added front brake
but the back wheels still don't have more brake power.
My next step is to connect one, maybe two 'blind' wheel
cylinder and see what happens. If this does not resolve the problem I will
try to use a Clutch Cylinder. All this will happen within the next two
to three weeks (today is Monday May 3rd, 1999), so stay tuned...
Gunnar
Gunnar
Thanks again to everyone who send me emails with suggestions, tips and solutions!!
Gunnar
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