Integration By Parts
Key: Keep track of your signs (+ or -) and remember your
integration rules. And becareful with your arithmetic and algebra as well; one mistake could make
entire problem real ugly..
The formula for parts is
òu * dv =
u * v - òv * du
where u and v are functions. Simply put, this means you'll be
integrating a function that can be broken into two simpler
functions (u and dv). ex * x is a good example.
Your two functions would be ex and x.
x * ex - ò
ex * 1 dx.
Since I picked u to be x and dv to be ex, it follows
that du is 1 dx and v is ex (the integral of ex).
Now integrating what's left inside the integral is simple.
The integral of ex dx is ex. So your answer
is x * ex - ex.
It's not always so easy. Sometimes you'll have to deploy parts
more than once. An example is ex * sin(x). Let's set
it up.
òex * sin(x) dx
Let u = sin(x) and dv = ex. Then du = cos(x) dx and v
= ex.
òex * sin(x) =
sin(x) * ex - ò
ex * cos(x)
We still can't integrate that. Do it again. Let u = cos(x) and dv
= ex. Then du = -sin(x) dx and v = ex.
òex * sin(x) =
sin(x) * ex - (cos(x) * ex
- ò ex * -sin(x)
)
Don't be afraid to use plenty of parentheses to help you keep your
signs straight. Cleaning up with some Algebra also helps
òex * sin(x) =
ex (sin(x) - cos(x))
- ò ex * sin(x)
Now we have something like A = B - A, or 2A = B, or A = B / 2. It's
just more Algebra; don't make anything more of it.
|
òex * sin(x) =
|
ex (sin(x) - cos(x))

2
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+ C
|
It is important to carry the original setup all the way
through the problem. That way you will know when you have A's on
both sides of the equation. An alternate way of doing this is
tabular integration. I recommend the above way (non-tabular) based
on my experiences if for no other reason.
| u and derivatives |
* |
v and integrals |
| |
|
ex |
| x |
¾ *+ ® |
ex |
|
¾ *- ® |
ex |
|
| ¾ *+ ® |
ex |
|
| ¾ *- ® |
ex |
|
| |
|
Probable Question: "How do I know what should be u and what
should be v?"
Find things that are easy to differentiate (take the derivative of)
and possibly go to 0 after a few times. Make that u. Make the other
thing v. Just think of it in an easy way.
That's integration by parts. Once again, only two different types
of problems to recognize. Once you've recognized if it repeats or
just goes through once you've already won half the battle. Things
that repeat and are cyclical will be in the trigonometric (including
the hyperbolics) and ex families, things that repeat but
go to 0 will be your xn types.